Universal - Maths tutor - Bikaner
1st lesson free
Universal - Maths tutor - Bikaner

Universal

  • Rate Rs 710
  • Response 1h
Universal - Maths tutor - Bikaner

Rs 710/hr

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths

Yesi am pankaj kumarIam study my math best my favourite subject math

  • Maths

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About Universal

We are asked to find the probability of getting exactly 2 heads in 3 coin tosses. Assuming the coin is fair, the probability of heads (p) = 0.5 and the probability of tails (q) = 0.5. Each toss is independent. This is a binomial probability problem, where: n = number of trials = 3 k = number of desired successes (heads) = 2 p = probability of success = 0.5 q = probability of failure = 0.5 The binomial probability formula is: 𝑃(π‘˜ heads in 𝑛 tosses)=(π‘›π‘˜)β‹…π‘π‘˜β‹…π‘žπ‘›βˆ’π‘˜ Plugging in the values: 𝑃(2 heads in 3 tosses)=(32)β‹…(0.5)2β‹…(0.5)1=3β‹…0.25β‹…0.5=0.375 Final Answer: The probability of getting exactly 2 heads in 3 coin tosses is 0.375 or 37.5%.

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The probability of getting exactly \(2\) heads in \(3\) coin tosses is \(0.375\). We are asked to find the probability of getting exactly 2 heads in 3 coin tosses. Assuming the coin is fair, the probability of heads (p) = 0.5 and the probability of tails (q) = 0.5. Each toss is independent. This is a binomial probability problem, where: n = number of trials = 3 k = number of desired successes (heads) = 2 p = probability of success = 0.5 q = probability of failure = 0.5 The binomial probability formula is: 𝑃(π‘˜ heads in 𝑛 tosses)=(π‘›π‘˜)β‹…π‘π‘˜β‹…π‘žπ‘›βˆ’π‘˜ Plugging in the values: 𝑃(2 heads in 3 tosses)=(32)β‹…(0.5)2β‹…(0.5)1=3β‹…0.25β‹…0.5=0.375 Final Answer: The probability of getting exactly 2 heads in 3 coin tosses is 0.375 or 37.5%.

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Rate

  • Rs 710

Pack prices

  • 5h: Rs 3550
  • 10h: Rs 7100

online

  • Rs 710/h

free lessons

The first free lesson with Universal will allow you to get to know each other and clearly specify your needs for your next lessons.

  • 1hr

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