Kayode - Maths tutor - Port Harcourt
1st lesson free
Kayode - Maths tutor - Port Harcourt

Kayode's email address and phone number have been validated.

Kayode

  • Rate Rs 177
  • Response 24h
  • Students

    Number of students Kayode has accompanied since arriving at Superprof

    1

    Number of students Kayode has accompanied since arriving at Superprof

Kayode - Maths tutor - Port Harcourt
  • 5 (2 reviews)

Rs 177/h

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Maths Logic

A dynamic and proficient Math tutor, incorporating sound knowledge of Engineering and Science to solving your mathematical problems. I teach the "understanding" of Math to aid your strength in not j

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Maths Logic

Lesson location

Recommended

Kayode is a respected member of our tutor community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.

About Kayode

I am a Civil Engineer but I've been passionate about teaching. I presently take home lessons and online tutorials in some other platforms. I engage the teaching of basic principle of mathematics and engineering to expose students to the concept behind each Mathematical problem and hence stir up your interest in not just the questions but the topic as a whole. Once you get the understanding of Mathematics, you can easily solve any question even beyond the scope of the particular question.

See more

About the lesson

  • Primary
  • Lower Secondary
  • O-level
  • +12
  • levels :

    Primary

    Lower Secondary

    O-level

    Lower Six

    Upper Six

    Continuous Professional Development

    Bachelor's Degree

    Master's

    Advanced Diploma

    Doctorate

    Association of Chartered Certified Accountants

    Chartered global management accountant

    BPTC

    MBA

    Pre-primary

  • English

All languages in which the lesson is available :

English

Find the largest of three consecutive odd numbers whose sum is 57. Solution: Let the largest be x Consecutive odd numbers increase/decrease by difference of 2. This implies, other two numbers are (x-2) and (x-4) So, the sum; x + (x-2) + (x-4) = 57 Hence, solving, we have; 3x - 6= 57 Add 6 to both sides, 3x = 63 Dividing both sides by 3 X = 21. This implies that, the largest number is 21. Other two numbers are; X-2 => 21-2 = 19 X-4 => 21-4 = 17 Check: The sum = 21+19+17= 57

See more

Rates

Rate

  • Rs 177

Pack prices

  • 5h: Rs 883
  • 10h: Rs 1,766

free lessons

The first free lesson with Kayode will allow you to get to know each other and clearly specify your needs for your next lessons.

  • 30mins

online

  • Rs -18/h

Similar Maths teachers in Port Harcourt